2x^2-x-666=0

Solution for 2x^2-x-666=0 equation:

2x^2-x-666=0

We add all the numbers together, and all the variables

2x^2-1x-666=0

a = 2; b = -1; c = -666;
Δ = b2-4ac
Δ = -12-4·2·(-666)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-73}{2*2}=\frac{-72}{4}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+73}{2*2}=\frac{74}{4}
=18+1/2
$